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no-type-alias

Disallow type aliases.

已弃用

此规则已被弃用,以支持 @typescript-eslint/consistent-type-definitions 规则。TypeScript 类型别名是一项普遍必需的语言功能;完全禁止它往往会适得其反。

¥This rule has been deprecated in favour of the @typescript-eslint/consistent-type-definitions rule. TypeScript type aliases are a commonly necessary language feature; banning it altogether is oftentimes counterproductive.

注意

如果你想要禁止某些分类的类型别名,请考虑使用 no-restricted-syntax。参见 故障排除和常见问题解答

¥If you want to ban certain classifications of type aliases, consider using no-restricted-syntax. See Troubleshooting & FAQs.

在 TypeScript 中,类型别名有三个用途:

¥In TypeScript, type aliases serve three purposes:

  • 给其他类型起别名,以便我们可以使用更简单的名称来引用它们。

    ¥Aliasing other types so that we can refer to them using a simpler name.

// this...
type Person = {
firstName: string;
lastName: string;
age: number;
};

function addPerson(person: Person) {
// ...
}

// is easier to read than this...
function addPerson(person: {
firstName: string;
lastName: string;
age: number;
}) {
// ...
}
  • 其行为有点像接口,提供一组必须存在于实现该类型的对象中的方法和属性。

    ¥Act sort of like an interface, providing a set of methods and properties that must exist in the objects implementing the type.

type Person = {
firstName: string;
lastName: string;
age: number;
walk: () => void;
talk: () => void;
};

// you know person will have 3 properties and 2 methods,
// because the structure has already been defined.
var person: Person = {
// ...
};

// so we can be sure that this will work
person.walk();
  • 就像类型之间的映射工具一样,允许快速修改。

    ¥Act like mapping tools between types to allow quick modifications.

type Immutable<T> = { readonly [P in keyof T]: T[P] };

type Person = {
name: string;
age: number;
};

type ImmutablePerson = Immutable<Person>;

var person: ImmutablePerson = { name: 'John', age: 30 };
person.name = 'Brad'; // error, readonly property

当使用别名时,类型别名不会创建新类型,它只是创建一个新名称来引用原始类型。因此,对基元和其他简单类型、元组、并集或交集进行别名有时可能是多余的。

¥When aliasing, the type alias does not create a new type, it just creates a new name to refer to the original type. So aliasing primitives and other simple types, tuples, unions or intersections can some times be redundant.

// this doesn't make much sense
type myString = string;

另一方面,使用类型别名作为接口可能会限制你执行以下操作的能力:

¥On the other hand, using a type alias as an interface can limit your ability to:

  • 重用你的代码:接口可以通过其他类型扩展或实现。类型别名不能。

    ¥Reuse your code: interfaces can be extended or implemented by other types. Type aliases cannot.

  • 调试你的代码:接口创建一个新名称,因此在调试应用时很容易识别对象的基本类型。

    ¥Debug your code: interfaces create a new name, so is easy to identify the base type of an object while debugging the application.

最后,映射类型是一种高级技术,将其保持开放状态很快就会成为应用的痛点。

¥Finally, mapping types is an advanced technique and leaving it open can quickly become a pain point in your application.

eslint.config.mjs
export default tseslint.config({
rules: {
"@typescript-eslint/no-type-alias": "error"
}
});

在线运行试试这个规则 ↗

示例

¥Examples

该规则不允许使用类型别名,而是使用接口和简化类型(基元、元组、并集、交集等)。

¥This rule disallows the use of type aliases in favor of interfaces and simplified types (primitives, tuples, unions, intersections, etc).

选项

该规则接受以下选项:

type ExpandedOptions =
| 'always'
| 'in-intersections'
| 'in-unions'
| 'in-unions-and-intersections'
| 'never';

type SimpleOptions = 'always' | 'never';

type Options = [
{
/** Whether to allow direct one-to-one type aliases. */
allowAliases?: ExpandedOptions;
/** Whether to allow type aliases for callbacks. */
allowCallbacks?: SimpleOptions;
/** Whether to allow type aliases for conditional types. */
allowConditionalTypes?: SimpleOptions;
/** Whether to allow type aliases with constructors. */
allowConstructors?: SimpleOptions;
/** Whether to allow type aliases with generic types. */
allowGenerics?: SimpleOptions;
/** Whether to allow type aliases with object literal types. */
allowLiterals?: ExpandedOptions;
/** Whether to allow type aliases with mapped types. */
allowMappedTypes?: ExpandedOptions;
/** Whether to allow type aliases with tuple types. */
allowTupleTypes?: ExpandedOptions;
},
];

const defaultOptions: Options = [
{
allowAliases: 'never',
allowCallbacks: 'never',
allowConditionalTypes: 'never',
allowConstructors: 'never',
allowGenerics: 'never',
allowLiterals: 'never',
allowMappedTypes: 'never',
allowTupleTypes: 'never',
},
];

¥Options

allowAliases

Whether to allow direct one-to-one type aliases. Default: "never".

该设置接受以下值:

¥The setting accepts the following values:

  • "always""never" 用于激活或停用该功能。

    ¥"always" or "never" to active or deactivate the feature.

  • "in-unions",允许在联合语句中使用别名,例如 type Foo = string | string[];

    ¥"in-unions", allows aliasing in union statements, e.g. type Foo = string | string[];

  • "in-intersections",允许在交集语句中使用别名,例如 type Foo = string & string[];

    ¥"in-intersections", allows aliasing in intersection statements, e.g. type Foo = string & string[];

  • "in-unions-and-intersections",允许在联合和/或交集语句中使用别名。

    ¥"in-unions-and-intersections", allows aliasing in union and/or intersection statements.

{ "allowAliases": "always" } 选项的正确代码示例:

¥Examples of correct code for the { "allowAliases": "always" } options:

// primitives
type Foo = 'a';

type Foo = 'a' | 'b';

type Foo = string;

type Foo = string | string[];

type Foo = string & string[];

type Foo = `foo-${number}`;

// reference types
interface Bar {}
class Baz implements Bar {}

type Foo = Bar;

type Foo = Bar | Baz;

type Foo = Bar & Baz;
Open in Playground

{ "allowAliases": "in-unions" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowAliases": "in-unions" } option:

// primitives
type Foo = 'a';

type Foo = string;

type Foo = string & string[];

type Foo = `foo-${number}`;

// reference types
interface Bar {}
class Baz implements Bar {}

type Foo = Bar;

type Foo = Bar & Baz;
Open in Playground

{ "allowAliases": "in-unions" } 选项的正确代码示例:

¥Examples of correct code for the { "allowAliases": "in-unions" } option:

// primitives
type Foo = 'a' | 'b';

type Foo = string | string[];

type Foo = `a-${number}` | `b-${number}`;

// reference types
interface Bar {}
class Baz implements Bar {}

type Foo = Bar | Baz;
Open in Playground

{ "allowAliases": "in-intersections" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowAliases": "in-intersections" } option:

// primitives
type Foo = 'a';

type Foo = 'a' | 'b';

type Foo = string;

type Foo = string | string[];

type Foo = `a-${number}` | `b-${number}`;

// reference types
interface Bar {}
class Baz implements Bar {}

type Foo = Bar;

type Foo = Bar | Baz;
Open in Playground

{ "allowAliases": "in-intersections" } 选项的正确代码示例:

¥Examples of correct code for the { "allowAliases": "in-intersections" } option:

// primitives
type Foo = string & string[];

type Foo = `a-${number}` & `b-${number}`;

// reference types
interface Bar {}
class Baz implements Bar {}

type Foo = Bar & Baz;
Open in Playground

{ "allowAliases": "in-unions-and-intersections" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowAliases": "in-unions-and-intersections" } option:

// primitives
type Foo = 'a';

type Foo = string;

type Foo = `foo-${number}`;

// reference types
interface Bar {}
class Baz implements Bar {}

type Foo = Bar;
Open in Playground

{ "allowAliases": "in-unions-and-intersections" } 选项的正确代码示例:

¥Examples of correct code for the { "allowAliases": "in-unions-and-intersections" } option:

// primitives
type Foo = 'a' | 'b';

type Foo = string | string[];

type Foo = string & string[];

type Foo = `a-${number}` & `b-${number}`;

type Foo = `a-${number}` | `b-${number}`;

// reference types
interface Bar {}
class Baz implements Bar {}

type Foo = Bar | Baz;

type Foo = Bar & Baz;
Open in Playground

allowCallbacks

Whether to allow type aliases for callbacks. Default: "never".

该设置接受以下值:

¥The setting accepts the following values:

  • "always""never" 用于激活或停用该功能。

    ¥"always" or "never" to active or deactivate the feature.

{ "allowCallbacks": "always" } 选项的正确代码示例:

¥Examples of correct code for the { "allowCallbacks": "always" } option:

type Foo = () => void;

type Foo = (name: string) => string;

class Person {}

type Foo = (name: string, age: number) => string | Person;

type Foo = (name: string, age: number) => string & Person;
Open in Playground

allowConditionalTypes

Whether to allow type aliases for conditional types. Default: "never".

{ "allowConditionalTypes": "always" } 选项的正确代码示例:

¥Examples of correct code for the { "allowConditionalTypes": "always" } option:

type Foo<T> = T extends number ? number : null;
Open in Playground

allowConstructors

Whether to allow type aliases with constructors. Default: "never".

该设置接受以下值:

¥The setting accepts the following values:

  • "always""never" 用于激活或停用该功能。

    ¥"always" or "never" to active or deactivate the feature.

{ "allowConstructors": "always" } 选项的正确代码示例:

¥Examples of correct code for the { "allowConstructors": "always" } option:

type Foo = new () => void;
Open in Playground

allowLiterals

Whether to allow type aliases with object literal types. Default: "never".

该设置接受以下选项:

¥The setting accepts the following options:

  • "always""never" 用于激活或停用该功能。

    ¥"always" or "never" to active or deactivate the feature.

  • "in-unions",允许在联合语句中使用文字,例如 type Foo = string | string[];

    ¥"in-unions", allows literals in union statements, e.g. type Foo = string | string[];

  • "in-intersections",允许在交集语句中使用文字,例如 type Foo = string & string[];

    ¥"in-intersections", allows literals in intersection statements, e.g. type Foo = string & string[];

  • "in-unions-and-intersections",允许在联合和/或交集语句中使用文字。

    ¥"in-unions-and-intersections", allows literals in union and/or intersection statements.

{ "allowLiterals": "always" } 选项的正确代码示例:

¥Examples of correct code for the { "allowLiterals": "always" } options:

type Foo = {};

type Foo = {
name: string;
age: number;
};

type Foo = {
name: string;
age: number;
walk: (miles: number) => void;
};

type Foo = { name: string } | { age: number };

type Foo = { name: string } & { age: number };
Open in Playground

{ "allowLiterals": "in-unions" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowLiterals": "in-unions" } option:

type Foo = {};

type Foo = {
name: string;
age: number;
};

type Foo = {
name: string;
age: number;
walk: (miles: number) => void;
};

type Foo = { name: string } & { age: number };
Open in Playground

{ "allowLiterals": "in-unions" } 选项的正确代码示例:

¥Examples of correct code for the { "allowLiterals": "in-unions" } option:

type Foo = { name: string } | { age: number };
Open in Playground

{ "allowLiterals": "in-intersections" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowLiterals": "in-intersections" } option:

type Foo = {};

type Foo = {
name: string;
age: number;
};

type Foo = {
name: string;
age: number;
walk: (miles: number) => void;
};

type Foo = { name: string } | { age: number };
Open in Playground

{ "allowLiterals": "in-intersections" } 选项的正确代码示例:

¥Examples of correct code for the { "allowLiterals": "in-intersections" } option:

type Foo = { name: string } & { age: number };
Open in Playground

{ "allowLiterals": "in-unions-and-intersections" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowLiterals": "in-unions-and-intersections" } option:

type Foo = {};

type Foo = {
name: string;
age: number;
};

type Foo = {
name: string;
age: number;
walk: (miles: number) => void;
};
Open in Playground

{ "allowLiterals": "in-unions-and-intersections" } 选项的正确代码示例:

¥Examples of correct code for the { "allowLiterals": "in-unions-and-intersections" } option:

type Foo = { name: string } | { age: number };

type Foo = { name: string } & { age: number };
Open in Playground

allowMappedTypes

Whether to allow type aliases with mapped types. Default: "never".

该设置接受以下值:

¥The setting accepts the following values:

  • "always""never" 用于激活或停用该功能。

    ¥"always" or "never" to active or deactivate the feature.

  • "in-unions",允许在联合语句中使用别名,例如 type Foo = string | string[];

    ¥"in-unions", allows aliasing in union statements, e.g. type Foo = string | string[];

  • "in-intersections",允许在交集语句中使用别名,例如 type Foo = string & string[];

    ¥"in-intersections", allows aliasing in intersection statements, e.g. type Foo = string & string[];

  • "in-unions-and-intersections",允许在联合和/或交集语句中使用别名。

    ¥"in-unions-and-intersections", allows aliasing in union and/or intersection statements.

{ "allowMappedTypes": "always" } 选项的正确代码示例:

¥Examples of correct code for the { "allowMappedTypes": "always" } options:

type Foo<T> = { readonly [P in keyof T]: T[P] };

type Foo<T> = { [P in keyof T]?: T[P] };

type Foo<T, U> =
| { readonly [P in keyof T]: T[P] }
| { readonly [P in keyof U]: U[P] };

type Foo<T, U> = { [P in keyof T]?: T[P] } | { [P in keyof U]?: U[P] };

type Foo<T, U> = { readonly [P in keyof T]: T[P] } & {
readonly [P in keyof U]: U[P];
};

type Foo<T, U> = { [P in keyof T]?: T[P] } & { [P in keyof U]?: U[P] };
Open in Playground

{ "allowMappedTypes": "in-unions" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowMappedTypes": "in-unions" } option:

type Foo<T> = { readonly [P in keyof T]: T[P] };

type Foo<T> = { [P in keyof T]?: T[P] };

type Foo<T, U> = { readonly [P in keyof T]: T[P] } & {
readonly [P in keyof U]: U[P];
};

type Foo<T, U> = { [P in keyof T]?: T[P] } & { [P in keyof U]?: U[P] };
Open in Playground

{ "allowMappedTypes": "in-unions" } 选项的正确代码示例:

¥Examples of correct code for the { "allowMappedTypes": "in-unions" } option:

type Foo<T, U> =
| { readonly [P in keyof T]: T[P] }
| { readonly [P in keyof U]: U[P] };

type Foo<T, U> = { [P in keyof T]?: T[P] } | { [P in keyof U]?: U[P] };
Open in Playground

{ "allowMappedTypes": "in-intersections" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowMappedTypes": "in-intersections" } option:

type Foo<T> = { readonly [P in keyof T]: T[P] };

type Foo<T> = { [P in keyof T]?: T[P] };

type Foo<T, U> =
| { readonly [P in keyof T]: T[P] }
| { readonly [P in keyof U]: U[P] };

type Foo<T, U> = { [P in keyof T]?: T[P] } | { [P in keyof U]?: U[P] };
Open in Playground

{ "allowMappedTypes": "in-intersections" } 选项的正确代码示例:

¥Examples of correct code for the { "allowMappedTypes": "in-intersections" } option:

type Foo<T, U> = { readonly [P in keyof T]: T[P] } & {
readonly [P in keyof U]: U[P];
};

type Foo<T, U> = { [P in keyof T]?: T[P] } & { [P in keyof U]?: U[P] };
Open in Playground

{ "allowMappedTypes": "in-unions-and-intersections" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowMappedTypes": "in-unions-and-intersections" } option:

type Foo<T> = { readonly [P in keyof T]: T[P] };

type Foo<T> = { [P in keyof T]?: T[P] };
Open in Playground

{ "allowMappedTypes": "in-unions-and-intersections" } 选项的正确代码示例:

¥Examples of correct code for the { "allowMappedTypes": "in-unions-and-intersections" } option:

type Foo<T, U> =
| { readonly [P in keyof T]: T[P] }
| { readonly [P in keyof U]: U[P] };

type Foo<T, U> = { [P in keyof T]?: T[P] } | { [P in keyof U]?: U[P] };

type Foo<T, U> = { readonly [P in keyof T]: T[P] } & {
readonly [P in keyof U]: U[P];
};

type Foo<T, U> = { [P in keyof T]?: T[P] } & { [P in keyof U]?: U[P] };
Open in Playground

allowTupleTypes

Whether to allow type aliases with tuple types. Default: "never".

该设置接受以下选项:

¥The setting accepts the following options:

  • "always""never" 用于激活或停用该功能。

    ¥"always" or "never" to active or deactivate the feature.

  • "in-unions",允许在联合语句中使用元组,例如 type Foo = [string] | [string, string];

    ¥"in-unions", allows tuples in union statements, e.g. type Foo = [string] | [string, string];

  • "in-intersections",允许在交集语句中使用元组,例如 type Foo = [string] & [string, string];

    ¥"in-intersections", allows tuples in intersection statements, e.g. type Foo = [string] & [string, string];

  • "in-unions-and-intersections",允许在联合和/或交集语句中使用元组。

    ¥"in-unions-and-intersections", allows tuples in union and/or intersection statements.

{ "allowTupleTypes": "always" } 选项的正确代码示例:

¥Examples of correct code for the { "allowTupleTypes": "always" } options:

type Foo = [number];

type Foo = [number] | [number, number];

type Foo = [number] & [number, number];

type Foo = [number] | ([number, number] & [string, string]);
Open in Playground

{ "allowTupleTypes": "in-unions" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowTupleTypes": "in-unions" } option:

type Foo = [number];

type Foo = [number] & [number, number];

type Foo = [string] & [number];
Open in Playground

{ "allowTupleTypes": "in-unions" } 选项的正确代码示例:

¥Examples of correct code for the { "allowTupleTypes": "in-unions" } option:

type Foo = [number] | [number, number];

type Foo = [string] | [number];
Open in Playground

{ "allowTupleTypes": "in-intersections" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowTupleTypes": "in-intersections" } option:

type Foo = [number];

type Foo = [number] | [number, number];

type Foo = [string] | [number];
Open in Playground

{ "allowTupleTypes": "in-intersections" } 选项的正确代码示例:

¥Examples of correct code for the { "allowTupleTypes": "in-intersections" } option:

type Foo = [number] & [number, number];

type Foo = [string] & [number];
Open in Playground

{ "allowTupleTypes": "in-unions-and-intersections" } 选项的错误代码示例:

¥Examples of incorrect code for the { "allowTupleTypes": "in-unions-and-intersections" } option:

type Foo = [number];

type Foo = [string];
Open in Playground

{ "allowTupleTypes": "in-unions-and-intersections" } 选项的正确代码示例:

¥Examples of correct code for the { "allowTupleTypes": "in-unions-and-intersections" } option:

type Foo = [number] & [number, number];

type Foo = [string] | [number];
Open in Playground

allowGenerics

Whether to allow type aliases with generic types. Default: "never".

该设置接受以下选项:

¥The setting accepts the following options:

  • "always""never" 用于激活或停用该功能。

    ¥"always" or "never" to active or deactivate the feature.

{ "allowGenerics": "always" } 选项的正确代码示例:

¥Examples of correct code for the { "allowGenerics": "always" } options:

type Foo = Bar<string>;

type Foo = Record<string, number>;

type Foo = Readonly<Bar>;

type Foo = Partial<Bar>;

type Foo = Omit<Bar, 'a' | 'b'>;
Open in Playground

进一步阅读

¥Further Reading

'## 资源'