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no-unsafe-argument

Disallow calling a function with a value with type any.

✅

在 ESLint 配置 中扩展"plugin:@typescript-eslint/recommended-type-checked" 可启用此规则。

💭

该规则需要 类型信息 才能运行。


TypeScript 中的 any 类型是类型系统中危险的 "应急方案"。 使用 any 会禁用许多类型检查规则，通常最好仅作为最后手段或在构建代码原型时使用。

英：The any type in TypeScript is a dangerous "escape hatch" from the type system. Using any disables many type checking rules and is generally best used only as a last resort or when prototyping code.

尽管你的意图是好的，但 any 类型有时可能会泄漏到你的代码库中。 使用 any 类型参数调用函数会产生潜在的安全漏洞和错误来源。

英：Despite your best intentions, the any type can sometimes leak into your codebase. Calling a function with an any typed argument creates a potential safety hole and source of bugs.

此规则不允许调用参数中包含 any 的函数。 这包括使用 any 类型元素作为函数参数来扩展数组或元组。

英：This rule disallows calling a function with any in its arguments. That includes spreading arrays or tuples with any typed elements as function arguments.

此规则还比较泛型类型参数类型，以确保你不会将泛型位置中的不安全 any 传递给需要特定类型的接收者。 例如，如果将 Set<any> 作为参数传递给声明为 Set<string> 的参数，则会出错。

英：This rule also compares generic type argument types to ensure you don't pass an unsafe any in a generic position to a receiver that's expecting a specific type. For example, it will error if you pass Set<any> as an argument to a parameter declared as Set<string>.

.eslintrc.cjs
module.exports = {
  "rules": {
    "@typescript-eslint/no-unsafe-argument": "error"
  }
};
在线运行试试这个规则 ↗

示例​

declare function foo(arg1: string, arg2: number, arg3: string): void;

const anyTyped = 1 as any;

foo(...anyTyped);
foo(anyTyped, 1, 'a');

const anyArray: any[] = [];
foo(...anyArray);

const tuple1 = ['a', anyTyped, 'b'] as const;
foo(...tuple1);

const tuple2 = [1] as const;
foo('a', ...tuple, anyTyped);

declare function bar(arg1: string, arg2: number, ...rest: string[]): void;
const x = [1, 2] as [number, ...number[]];
foo('a', ...x, anyTyped);

declare function baz(arg1: Set<string>, arg2: Map<string, string>): void;
foo(new Set<any>(), new Map<any, string>());
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在某些情况下，规则允许将 any 参数传递到 unknown。

英：There are cases where the rule allows passing an argument of any to unknown.

允许的 any 到 unknown 分配示例：

英：Example of any to unknown assignment that are allowed:

declare function foo(arg1: unknown, arg2: Set<unknown>, arg3: unknown[]): void;
foo(1 as any, new Set<any>(), [] as any[]);
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何时不使用它​

如果你的代码库有许多现有的 any 或不安全代码区域，则可能很难启用此规则。 在项目的不安全区域中，在增加类型安全性之前，跳过 no-unsafe-* 规则可能会更容易。 你可以考虑在这些特定情况下使用 ESLint 禁用注释，而不是完全禁用此规则。

英：If your codebase has many existing anys or areas of unsafe code, it may be difficult to enable this rule. It may be easier to skip the no-unsafe-* rules pending increasing type safety in unsafe areas of your project. You might consider using ESLint disable comments for those specific situations instead of completely disabling this rule.

选项​

该规则不可配置。

资源​